page1
This lesson is about length contraction.
I'm adding two people, called
and
. In their reference frame, they
are 2 units away from each other.
page2
Now I can change the velocity and see that they move closer to each other. If
I pick a velocity of 0.87, then the scaling factor
is about 2. That means that in our
current reference frame, the distance between them is about
as big
as in their reference frame.
page3
It is difficult to derive length contraction just from drawing pictures. So
I won't try. There are some nice references about the this in the
Lorentz transformation section on the
discussion page under the help menu.
page4
As with time dilation, it seems like there is a paradox. If
thinks
is shorter, and
thinks
is shorter, which is right?
page5
The classic way to talk about this paradox is by trying to drive a train into a
barn. Let's add a train in our current reference frame.
Now we'll adjust our velocity to be the same as
and
.
Notice that the train is shorter now.
page6
I'm going to adjust the time so that the train has moved past the two people,
and then I'm going to add a barn. The barn is positioned so that the train
is completetly inside it.
page7
But when I adjust the velocity so that I'm looking at the train's reference, the
train no longer fits in the barn. What happened?
page8
Let's go back to the barn's reference frame.
I'm going to add two events:
a red one corresponds to the left hand side of the train is inside the barn,
and a blue event is that the right hand side is inside the barn. In the barn's
reference frame, these events happen at the same time.
page9
But in the train's reference frame, the two events do not happen at the same
time. As we move the time forward and back, we can see that they mean the same
thing: the red event means the left hand side of the train is inside the barn,
and the blue event is the right hand side of the train is inside the barn.
However, by the time the left hand side is inside, the right hand
side has already passed beyond the edge of the barn, causing expensive
damage.
The paradox is resolved by saying that the two different reference frames do
not agree on which events are simultaneous.